Practice Reasoning Questions SSC CGL, CHSL, CPO Exams Set-18:
Dear Readers, Important Practice Reasoning Questions for SSC CGL,SSC CHSL, SSC CPO Exams was given here, candidates those who are preparing for those exams can use this material.
1).There
are some boys and dogs at a place. If the total number of heads is 7 and total
number of heads is 7 and the total number of legs is 20, how many boys and dogs
are there?
a)
2, 5
b)
3, 4
c)
4, 3
d)
5, 2
2).Ram
travels 10 km towards the North, turns left and travels 4 km and then again
turns right and covers another 5 km and then turns right and travels another 4
km. How far is he from the starting point?
a)
5 km
b)
10 km
c)
15 km
d)
19 km
3).A,
B, C and D are four friends. Average age of A and C is 35 yr and that of B and
D is 40 yr. Average age of B, C and D is 40 yr. The sum of the ages of A and D
is equal to that of B and C. Find out the ages (in yr) of A, B, C and D.
a)
20, 30, 40, 50
b)
20, 25, 30, 35
c)
30, 35, 40, 45
d)
30,40, 50, 60
4).A
word is given in capital letters. It is following by four words. Out of these
four words, three cannot be formed from the letters of the word in capital
letters. Point out the word which can be formed from the letters of the given
word in capital letters?
PHILANTHROPIST
a)
FIST
b)
LARK
c)
HYPOCRISY
d)
PISTON
5).
A
word given in capital letters is followed by four words. Out of these only one
cannot be formed by using the letters of the given word. Find out that word.
ENCYCLOPEDIA
a)
CYCLE
b)
PENCIL
c)
YOKE
d)
DIAL
6).
a)
35
b)
37
c)
45
d)
47
7).
|
9
|
6
|
8
|
|
5
|
8
|
4
|
|
7
|
4
|
?
|
|
11
|
2
|
7
|
a)
4
b)
7
c)
3
d)
6
8).From
amongst the given alternative, select the one in which the set of numbers is
most like the set of numbers given below.
Given set (7, 12, 22, 37)
a)
2, 7, 12, 32
b)
3, 8, 18, 33
c)
4, 8, 19, 34
d)
8, 13, 22, 38
9).In
a caravan, in addition to 50 hens, there are 45 goats and 8 camels with some
keepers. If the total number of legs be 224 more than the number of heads in
the caravan, the number of keepers is
a)
5
b)
8
c)
10
d)
15
10).Mayank
ranks 11th from the top and 25th from the bottom. How
many students are there in the class?
a)
38
b)
35
c)
40
d)
32
Answers:
1).
c) 2). c) 3).
c) 4). d) 5).
c) 6). b) 7).
c) 8). b) 9).
d) 10). b)
Solution:
1).
Number of heads = B + D = 7 …(i)
Number of legs = 2B + 4D = 20 …(ii)
From statements (i) and (ii)
B = 4 and D = 3
Answer: c)
2).
Required distance = 10 + 5 = 15 km
Answer: c)
3).
A + C= 70 yr
B + D = 80 yr
B + C + D = 120 yr
C = 40 yr and A = 30 yr
A + D = B + C
30 + D = B + 40
D – B = 10 yr
B = 35 yr and D = 45 yr
Answer: c)
4).
There is no ‘F’ letter in the keyword
Therefore, the word FIST cannot be formed
There is no ‘K’ letter in the keyword
Therefore, the word LARK cannot be formed
There is no ‘C’ or ‘Y’ letter in the keyword. Therefore,
the word HYPOCRISY cannot be formed
Hence, PISTON word can be formed from the
given word.
Answer: d)
5).
There is no’K’ letter in the keyword. Therefore, the word YOKE cannot be
formed.
Answer: c)
6).
As, 5 × 6 + 3 × 3 = 39
And 7 × 5 + 4 × 4 = 51
Similarly, 5 × 5 + 3 × 4 = 37
Answer: c)
7).
As, 9 + 7 – 5 =11
And 6 + 4 – 8 = 2
8 + ? – 4 = 7
? = 11 – 8 = 3
Answer: b)
8).
As,
7 + 5 = 12,
12 + 10 = 22
And 22 + 15 = 37
Similarly, 3 + 5 = 8;
8 + 10 = 18
And 18 + 15
= 33
Answer: b)
9).
Let the number of keepers = x
Then, total number of legs = 2 × 50 + 4 × 45 +
4 × 8 + 2x
=2x + 100 + 180 + 32 = 2x + 312 [Hen = 2 legs,
Goat = 4 legs, Camel = 4 legs and keeper = 2 legs]
And total number of heads = 50 + 45 + 8 + x =
103 + x
[Hen = Goat + Camel + Keeper = One head]
According to the question,
(2x + 312) = (103 + x) + 224
x = 327 – 312
x = 15
So, required number of keepers = x = 15
Answer: d)
10).
Total number of students in the class = 11 + 25 – 1 = 35
Answer: b)
