__Practice Aptitude Questions__:

**With Solutions SSC CGL, CHSL Exams Set-26**
Dear Readers, Important Aptitude Questions for SSC CGL,CHSL Exam was given here with solutions, candidates those who are preparing for those exams can use this material.

**1).**A sum of money placed at compound interest triples itself in 5 yr. In how many years will it amount to nine times itself?

a)
12

b)
10

c)
15

d)
18

**2).**A number divided by 56 gives 29 as remainder. If the same number is divided by 8, the remainder will be

a)
4

b)
5

c)
6

d)
7

**3).**What is the value of √7.84 + √0.0784 + √0.000784 + √0.00000784 ?

a)
3.08

b)
3.108

c)
3.1008

d)
3.1108

**4).**If 1(2 / 3)÷(2 / 7) × (x / 7) = 1(1 / 4) × (2 / 3) ÷ (1 / 6) then find the value of x.

a)
0.006

b)
1/6

c)
0.6

d)
6

**5).**A man has 100 kg of sugar, part of which he sold at 7% profit and rest at 17% profit. He gained 10% on the whole. How much did he sell at 7% profit?

a)
65
kg

b)
35
kg

c)
30
kg

d)
70
kg

**6).**The price of rice is reduced by 2%. How many kilograms of rice can now be bought for the money which was sufficient to buy 49 kg of rice earlier?

a)
48

b)
49

c)
50

d)
51

**7).**The ages of Vaibhav and Jagat are in the ratio of 12 : 7. After 6 yr, the ratio of their ages will be 3 : 2. What is the difference in their ages?

a)
8
yr

b)
12
yr

c)
9
yr

d)
10
yr

**8).**If both the radius and height of a right circular cone are increased by 20%, its volume will be increased by

a)
20%

b)
40%

c)
60%

d)
72.8%

**9).**In an examination, 52% students failed in Hindi and 42% in English. If 17% failed in both the subjects, what percentage of students passed in both the subjects?

a)
38

b)
33

c)
23

d)
18

**10).**The least number, which must be added to 6709 to make it exactly divisible by 9, is

a)
5

b)
4

c)
7

d)
2

__Answers__**:**

**1). b) 2). b) 3). d) 4). d) 5). d) 6). c) 7). d) 8). d) 9). c) 10). a)**

__Solution:__**1).**Let Rs. P be the Principal.

3P
= P (1 + r / 100)

^{5}
3
= (1 + r / 100)

^{5}
On
squaring both sides, we get

3

^{2}= (1 + r / 100)^{10 }….(i)
Let
the sum will be nine times in n yr.

9P
= P (1 + r / 100)

^{n}
3

^{2}= (1 + r / 100)^{n }….(ii)
On
comparing Eqs (i) and (ii) we get n = 10 yr

**Answer: b)**

**2).**Let the number be x.

Then,
according to the question,

x
= 56k + 29

Then,
x = (8 × 7k) + (8 × 3) + 5

=
8 × (7k + 3) + 5

Therefore,
when x is divided be 8, the required remainder = 5

**Answer: b)**

**3).**√7.84 + √0.0784 + √0.000784 + √0.00000784

= √784 / 100 + √ 784 / 10000 + √784 / 1000000
+ √784 / 100000000

=
(28 / 10) + (28 / 100) + (28 / 1000) + (28 / 10000)

=
2.8 + 0.28 + 0.028 + 0.0028

=
3.1108

**Answer: d)**

**4).**Given expression,

(5
/ 3) × (7 / 2) × (x / 7) = (5 / 4) × (2 / 3) × 6

x
= (2 × 6) / 2

x
= 6

**Answer: d)**

**5).**By the rule of alligation, we have

Now
the quantity of sugar sold at

7%
is given by = (7 / 10) × 100 = 70kg

**Answer: d)**

**6).**Let the original price per kg be Rs. 100

Reduced
price = Rs. 98

Then,
the amount sufficient for 49 kg is = 49 × 100 = RS. 4900

Amount
to be bought = 4900 / 98 = 50kg

**Answer: c)**

**7).**Let the present age of Vaibhav = 12x yr

And
present age of Jagat = 7x yr

According
to the question,

(12x
+ 60 / (7x + 6) = 3 / 2

24x
+ 12 = 21x + 18

24x
– 21x = 18 – 12

3x
= 6

x
= 6 / 3 = 2

Required
difference = 12x – 7x = 5x = 5 × 2 = 10 yr

**Answer: d)**

**8).**If height and radius both of a cylinder change by x%, then volume changes by

=
[ 3x + (3x

^{2}/ 100) + (x^{3}/ 100^{2})]%
=
[3 × 20 + (3 × 20 × 20) / 100 + (20 × 20 × 20) / 10000 ]

=
60 + 12 + 0.8 = 72.8%

**Answer: d)**

**9).**Let the total number of students = 100

Number
of students who failed in Hindi or English or both = 52 + 42 – 17 = 77

Number
of students who passed in both subjects = 100 – 77 = 23

Required
percentage = 23%

**Answer: c)**

**10).**A number is divisible by 9, if the sum of its digits is divisibke by 9.

Here
6 + 7 + 0 + 9 = 22

Now,
22 + 5 = 27, which is divisible by 9. Hence, 5 must be added to 6709.

**Answer: a)**

For more Aptitude Practice Sets - Click here