Dear Readers, Important Aptitude Questions for RRB/SSC/FCI Exam was given here with solutions, candidates those who are preparing for those exams can use this material.
1).25%
of what amount of money is equal to 12 (1 / 2)% of Rs. 180?
a)
Rs. 120
b)
Rs. 75
c)
Rs. 80
d)
Rs. 90
2).Rs.
5625 are divided among A, B, and C so that A receives 1 / 2 as much as B and C
together receive and B receives 1 / 4 of what A and C together receive. The
share of A is more that B by
a)
Rs. 750
b)
Rs. 775
c)
Rs. 1500
d)
Rs. 1600
3).The
radii of two circles are 5 cm and 3 cm, the distance between their centres is
24 cm. Then, the length of the transverse common tangent is
a)
16 cm
b)
15√2 cm
c)
16√2 cm
d)
15 cm
4).The
average age of a class is 15.8 yr. The average age of the boys in the class is
16.4 yr and that of the girls is 15.4 yr. What is the ratio of boys to girls in
the class?
a)
1 : 2
b)
2 : 3
c)
3 : 4
d)
Cannot be determined
5).A
man covers half of his journey at 6 km / h and the remaining half at 3 km / h.
His average speed is
a)
9 km / h
b)
4.5 km / h
c)
4 km / h
d)
3 km / h
6).The
price of a jewel, passing through three hands, rises on the whole by 65%. If
the first and the second sellers earned 20% and 25% profit respectively, Find
the percentage profit earned by the third seller?
a)
5%
b)
10%
c)
15%
d)
20%
7).x%
of x is the same as 10% of
a)
x / 100
b)
x2 / 10
c)
x3 / 10
d)
None of these
8).A
boat running downstream covers a distance of 10 km in 2h. While coming back
stream the boat takes 5 h to cover the same distance. If the speed of the
current is 1.5 km / h, what is the speed of the boat in still water?
a)
2.5 km / h
b)
3.5 km / h
c)
5.3 km / h
d)
4.3 km / h
9).If
the simple interest on a sum of money for 2 yr at 5% per annum is Rs. 50, what
will be the compound interest on the same sum at the same rate for the same
time?
a)
Rs. 51.25
b)
Rs. 52
c)
Rs. 54.25
d)
Rs. 60
10).HCF
of x2 – y2 and x3 – y3 is
a)
x - y
b)
x3 – y3
c)
x2 – y2
d)
(x + y)( x2 + xy + y2)
Answers:
1).
d) 2). a) 3).
c) 4). b) 5).
c) 6). b) 7).
b) 8). a) 9).
a) 10). b)
Solution:
1).
Let required amount of money be Rs. x. Then,
x × 25% = 180 × 12(1 / 2)%
x = (180 × 12.5) / 25 = Rs.
90
Answer: d)
2).
A = 1 / 2(B + C)
B + C = 2A
A + B + C = 3A
3A = 5625
B = 1.125
A = 1875
B = 1 / 4(A + C)
A + C = 4B
A + B + C = 5B
5B = 5625
A = 1875
(A – B) = Rs. 1875 – 1125 = Rs. 750
Answer: a)
3).
Transverse common tangent
=
√[ d2 – (r1 + r2)2]
=
√[ (24)2 – (5 + 3)2]
=
√(576 – 64) = √512 = 16√2 cm
Answer: c)
4).
Let the required ratio be x : 1, then
(x × 16.4) + (1 × 15.4) = (x + 1) × 15.8
16.4x + 15.4 = 15.8x + 15.8
(16.4x – 15.8x) = (15.8 – 15.4)
0.6x = 0.4
x = 4 / 6 = 2 / 3
Required ratio = 2 / 3 : 1 = 2 : 3
Answer: b)
5).
Average speed = 2xy / (x + y) km / h = (2 × 6 × 3) / (6 + 3) km / h = 4 km / h
Answer: c)
6).
Let the original price of the jewel be Rs. P and let the profit earned by the
third seller be x%
Then, (100 + x)% of 125% of 120% of P = 165%
of P
= { [ (100 + x) / 100 ] × (125 / 100) × (120 /
100) × P} = [ (165 / 100) × P]
(100 + x ) = [ ( 165 × 100 × 100) / (125 ×
120) ] = 110
x = 10%
Answer: b)
7).
Let x% of x = 10% of y. then,
(x / 100) × x = (10 / 100) × y
y / 10 = x2 / 100
y = x2
/ 10
Answer: b)
8).
Speed
downstream = 10 / 2 km / h = 5 km/h
Speed upstream = 10 / 5 km/h = 2 km/h
Speed of boat in still water = 1 / 2(5 + 2)
km/h = 3.5 km/h
Answer: a)
9).
Sum = Rs.[ (100 × 50) / (2 × 5) ] = Rs. 500
Cl = Rs. [ 500 ×
(1 + (5 / 100)2 ) – 500]
=
Rs. [ 500 × (21 / 20) × (21 / 20) – 500]
=
Rs. (551.25 – 500) = Rs. 51.25
Answer: a)
10).
x2 – y2 = (x + y)(x – y)
x3 – y3 = (x - y)( x2
+ xy + y2)
HCF = (x – y)
Answer: b)
