Practice Aptitude Questions (Arithmetic) With Solutions Set-57:
Dear Readers, Important Aptitude Questions for SSC/FCI Exam was given here with solutions, candidates those who are preparing for those exams can use this material.
1).A bag
contains 1 – rupee, 50 – paise and 25 paise coins in the ratio of 3 : 4 : 4. If
the total amount is Rs. 90, the number of 1 rupee coins is
a)
30
b)
15
c)
45
d)
60
2).A jar
contains 40 white and 120 black marbles. How many white marbles must be added
to the jar so that 50% of the marbles become white?
a)
80
b)
60
c)
50
d)
40
3).A and B
can do a piece of work in 12 days, B and C can do it in 18 days, C and A can do
it in a 20 days. The time taken by A, B and C together to do the same piece of
work will be
a)
12
(10/17) days
b)
10
(1/17) days
c)
10
(10/17) days
d)
13
(10/17) days
4).40 men can
finish a work in 80 days, working 10 hours per day. How many men can finish the
same work in 20 days, working 8 hours per day?
a)
400
men
b)
200
men
c)
600
men
d)
100
men
5).Two pipes
A and B can fill a tank in 12 hours and 15 hours respectively and C can empty
it in 10 hours. If all three pipes are opened at 5 : 30 am, at what time will
half of the tank be filled
a)
3
: 30 pm
b)
3
: 20 am
c)
3
: 00 pm
d)
5
: 30 pm
6).The radius
of a wheel is 84 cm. it completes 600 rotations in 10 minutes. What is its
speed ( in kmph)?
a)
28
b)
24.008
c)
19.008
d)
16
7).The speed
of stream is 6 Kmph. A motor boat goes 12 km upstream and comes back to the
starting point in 90 minutes. The speed of the motorboat ( in kmph ) in still
water is
a)
22
b)
16
c)
18
d)
12
8).Water
flowing at the rate of 10 kmph through a pipe of diameter 28 cm into a
rectangular tank which is 100 m and long and 88m wide. The time taken ( in
hours ) for 14 cm rise in water level in the tank will be
a)
8
hours
b)
6
hours
c)
4
hours
d)
2
hours
9).The mean
of 15 numbers is 40. Later on, it was observed that 25 and 15 were wrongly
taken as 52 and 51. The correct mean is
a)
33.8
b)
35.8
c)
38.5
d)
36.0
10).The product
of two numbers is 4056 and their HCF is 26. The number of such pairs is
a)
1
b)
2
c)
3
d)
4
Answers:
1).c) 2). a) 3). c) 4).b) 5).a) 6). c) 7).
c) 8). c) 9).b) 10).b)
Solution:
1). Let the
numbers of coins be 3x, 4x and 4x respectively,
Then, the value of coins = (3x / 1)
+ (4x / 2) + (4x / 4)
= 3x + 2x + x = 6x
Given 6x = 90
∴ x = 15
Number of 1 rupee coins = 3x = 3 ×
15 = 45
Answer:
c )
2). Suppose x
white marbles are added.
Then, (x + 40) / 120 = 50 / 50
Or, x + 40 – 120
Or, x = 80
Answer:
a )
3). (A + B)
can do 1/12 work in 1 day,
Again B + C can do 1/18 work in 1
day,
And C + A can do 1/20 work in 1 day.
Now, 2 (A + B + C)’s 1 day’s work
= (1/12) + (1/18) + (1/20) = (30 +
20 + 18) / 360 = 68 / 360
∴ ( A + B + C)’s 1 day’s work = 68 /
720
Hence A, B and C will complete the
work in 180/17 = 10 (10/17) days
Answer:
c)
4). 40 men,
working 10 hours a day can do a piece of work in 80 days.
Suppose x men can do the same piece
of work in 20 days, working 8 hours a day,
Now, M1 D1 H1
= M2 D1 H2
∴ 40 × 80 × 10 = x × 20 × 8
x = (40 × 80 × 10) / (20 × 8) = 200
men
Answer:
b )
5). A and B
can fill the tank in 12 and 15 hours respectively
C can empty the tank in 10 hours,
So, A, B, and C can fill in 1 hour
(1 / 12) + (1 / 15) – (1 / 10) = (5
+ 4 – 6) / 60 = 3 / 60 = 1 / 20
All three pipes are opened at 5 : 30
am.
∴ they will fill 1 / 2 of the tank
in
(1 / 2) × 20 = 10 hours from 5 : 30
am
∴ Time = 5 : 30 am + 10 hours = 15 :
30
= 3 : 30 pm
Answer:
a )
6). Radius of
the wheel is 84 cm.
∴ Circumference of the wheel = 2
= 2 × (22 / 7) × 84 = 528 cm
∴ Distance covered in 10 minutes
= 528 × 600 = 316800 cm = 3.168 km
(100 cm = 1 m and 1000 m = 1 km)
∴ Time = 10 mnutes = 10 / 60 hours =
1 / 6 hours
∴ Speed = Distance / Time = 3168 /
(1/6) kmph
= 19.008 kmph
Answer:
c)
7). Speed of
the current = 6 kmph
Let the speed of motorboat in still
water be x kmph
Speed downstream = ( x + 6) kmph
Speed upstream = ( x – 6) kmph
Now, according to the question,
[12 / (x – 6)] + [12 / (x + 6)] = 90
/ 60 = 3 / 2
Or, (12x + 72 + 12x – 72) / (x2
– 36) = 3 / 2
Or, 24x / (x2 – 36) = 3 /
2
Or, x2 – 16x – 36 = 0
Or, x2 – 18x + 2x – 36 =
0
Or, x(x – 18) + 2(x – 18) = 0
Or,(x – 18) (x + 2) = 0
x = 18 kmph
∴ Neglect negative value
Answer:
c)
8). Volume of
water = 100 × 88 × 14 × 100 × 100 cm3
∴ Volume
of water filled in 1 hour
= ( 22/7) × 14 × 14 × 10000 × 100 cm3
Reqd time = (10000 × 8800 × 14) /
[(22/7) × 14 × 14 × 1000000 ]
= 4 hours
Answer:
c )
9). The wrong
sum = 15 × 40 = 600
The correct sum = 600 – ( 52 + 51 )
+ ( 25 + 15) = 600 + 40
103 = 537
The correct mean = 537 / 15 = 35.8
Answer:
c)
10). HCF of
two numbers is 26
Let
the numbers be 26a and 26b
∴
26a × 26b = 4056
ab
= 4056 / (26×26) = 6
(a,
b) = ( 1,6) (2,3)
So
required numbers are ( 26 × 1, 26 × 6) and ( 26 × 2, 26 × 3)
Number
of such pairs = 2
Answer:
b)
