Quantitative Aptitude Practice Questions (With Solutions) Set-28:
List of Practice Questions for Upcoming SSC CGL Tier II Exam was given here with solutions, candidates those who are preparing for those exams can use this material
1).In
ABC, two points D and E are taken on the lines AB and BC respectively in such a
way that AC is parallel to DE. Then ∆ABC and ∆DBE are
a)
Similar
only if D lies outside the line segment AB
b)
Congruent
only if D lies outside the line segment AB
c)
Always
similar
d)
always
congruent
2).The
internal bisectors of the angles B and C of a triangle ABC meet at I.
If ∠BIC = ∠A /2 + X, then X is equal to
a)
60°
b)
30°
c)
90°
d)
45°
3).In
a ∆ABC, the medians AD, BE and CF meet at G, then which of the following is
true?
a)
AD+BE+CF>
½(AB+BC+AC)
b)
2(AD+BE+CF)>(AB+BC+AC)
c)
3(AD+BE+CF)>4(AB+BC+AC)
d)
4(AD+BE+CF)>3(AB+BC+AC)
4).ST
is a tangent to the circle at P and QR is a diameter of the circle. If ∠RPT=50°,
then the value of ∠SPQ is
a)
40
b)
60
c)
80
d)
100
5).The
greatest number that will divide 729 and 901 leaving remainders 9 and 5
respectively, is
a)
15
b)
16
c)
19
d)
20
6).On
simplification,
(1
- ½)(1 - 1/3)(1 - 1/4)……..(1 - 1/n) is equal to
a)
1/n
b)
2/n
c)
2(n-1)
/ n
d)
1
/ n(n-1)
7).
Find the sum of first five terms of the following series:
{1/(1×4)} +{1/(4×7)}+{1/(7×10)}+……..+……
a)
9/32
b)
7/16
c)
5/16
d)
1/210
8).
5349 is added to 3957. Then 7062 is subtracted from the sum. The result is not divisible by
a)
4
b)
3
c)
7
d)
11
9).
How many men need to be employed to complete a job in 5 days. If 15 men can
complete 1/3 of the job in 7 days?
a)
20
b)
21
c)
45
d)
63
10).
The product of all the prime numbers between 80 and 90 is
a)
83
b)
89
c)
7387
d)
598347
Answers:
1). c) 2). c) 3). d) 4). a) 5). b) 6). a) 7). c) 8). c) 9). d) 10).c )
Check here the Solution for above Aptitude Questions:
1).
Answer: c)
2).
∟BIC =(∟A/2) + x, Then x=90°
Answer: c)
3).
4(AD+BE+CF)>3(AB+BC+AC)
Answer: d)
4).
∟SPQ =40°
Answer: a)
5).
Required number =GCD of(729-9 and (901-5)
=GCD of(720, 896)
Now720=24×5×9
896=27×7
∴GCD of (720, 896)
=24=16
Required number =16
Answer: b)
6).
(1 - 1/2)(1 - 1/3)(1 - 1/4)……(1 - 1/n)
=1/2.2/3.3/4.4/5…… n-1 /n =1/n
Answer: a)
7).
Result = 1/ n(n+3) = 1/3[1/n - 1/n+3]
1/1×4 +1/4×7 + 1/7×10 + (1/10×13) × (1/13×16)
=1/3(1/1 - 1/4)+1/3(1/4 - 1/7)+1/3(1/7 - 1/10)+1/3(1/10
- 1/13)+1/3(1/13 - 1/16)
=1/3[1/1-1/4+1/4-1/7+1/7-1/10+1/10-1/13+1/15-1/16]
=1/3[1-1/16] =1/3(15/16)=5/16
Answer: c)
8).
5349+3957-7062 =2244
2244 is not divisible by 7.
Answer:
c)
9).
15 men can complete 1/3 of a job in 7 days.
→15 men can complete the job in 7×3 =21
days
Now
M1
=15; D1=21
M1=?;
D2=5
Formula
M1D1=M2× D2
→15×21
=M2×5
M2=15×21 /5 =3×21 =63 days
Answer: d)
10).
Prime members between 80 and 90 are 83 and 89
Product =83× 89 =7387
Answer: c)
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