Aptitude Shortcut methods For Ratio and Proportion - Download in PDF

Aptitude Shortcut methods For Ratio and Proportion - Download in PDF:
Aptitude Shortcut methods and tricks for Ratio and Proportion were given below. Candidates those who are preparing for SSC/FCI and all other competitive Exams can also download this in PDF.

QUESTION:
A bag contains 1rupee, 50 paise and 10 paise coins in the ratio 3:4:10 amounting to Rs.102. Find the number of 10paise coins?

GIVEN:
Denomination of coins = 50p, 10p, 1 rupee
Total amount = Rs.102
Ratio of coins = 3:4:10

SOLUTION:

NORMAL METHOD
Let the number of 1rupee (100 paise), 50p, 10p coins be 3x, 4x and 10x respectively
Since the total amount is given in Rupees (102), the 50p and 10p has to be converted into rupees

Therefore,
1 rupee = 1 rupee
50p = [50/100] = ½ rupee
10p = [10/100] = [1/10] rupee

Multiply the converted rupees with the given ratios so,
1×3x + (½ ×4x) + [(1/10)×10x]

à 3x+(4x/2)+(10x/10)
We will get,
à 3x + 2x + 1x = 102
=> 6x = 102
=> x = [102/6] = 17
Now, the number of 10p coins are asked in the question, the ratio term of 10p =10x
Therefore, no. of 10p coins in the bag = 10x = [10×17] = 170 coins

SHORT METHOD


3×100p: 4×50p: 10×10p


Sum of all parts 6= Rs.102
Single part 1=?                               
x = Rs. 102 /6 = 17
There for no. of 10p = 10×17 = 170coins


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