Aptitude Shortcut methods and tricks for Ratio and Proportion
were given below. Candidates those who are preparing for SSC/FCI and all
other competitive Exams can also download this in PDF.

**QUESTION:**

A bag contains 1rupee, 50 paise and 10 paise
coins in the ratio 3:4:10 amounting to Rs.102. Find the number of 10paise
coins?

__GIVEN:__

Denomination of coins = 50p, 10p, 1 rupee

Total amount = Rs.102

Ratio of coins = 3:4:10

__SOLUTION:__

**NORMAL METHOD**

Let the number of 1rupee (100 paise), 50p, 10p
coins be 3x, 4x and 10x respectively

Since the total amount is given in Rupees
(102), the 50p and 10p has to be converted into rupees

Therefore,

1 rupee = 1 rupee

50p = [50/100] = ½ rupee

10p = [10/100] = [1/10] rupee

Multiply the converted rupees with the given ratios
so,

1×3x + (½ ×4x) + [(1/10)×10x]

à
3x+(4x/2)+(10x/10)

We will get,

à
3x + 2x + 1x = 102

=> 6x = 102

=> x = [102/6] = 17

Now, the number of 10p coins are asked in the
question, the ratio term of 10p =10x

Therefore, no. of 10p coins in the bag = 10x =
[10×17] =

**170 coins**

**SHORT METHOD**

3×100p: 4×50p: 10×10p

Sum of all parts 6= Rs.102

Single part 1=?

x = Rs. 102 /6 = 17

**There for no. of 10p = 10×17 = 170coins**

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