Quantitative Aptitude for SSC
CGL Mains/FCI Exam Practice Set-18:

Direction(1-5): The Pie chart given here
represents the domestic expenditure of a family in percent. Study the chart and
answer the following questions if the total monthly income of the family is
Rs.33,650.

A : Expenditure on Food

B : Expenditure on house rent

C: Expenditure on entertainment

D : Expenditure on education and maintenance
of children

E : Medical and miscellaneous expenditure

F: Deductions towards provident fund

1).The measure of the central angle of the
sector representing expenditure on education and maintenance of children is

a)45°

b)60°

c)80°

d)90°

Answer: d)

100% =360°
25%=360/100×25 =90°

2).The house rent per month is

a)Rs.6000

b)Rs.6152

c)Rs.6057

d)Rs.6048

Answer: c)

Explanation:
House rent per month =18% of Rs.33650
=Rs.18×33650/100
=Rs.6057

3).The annual savings in the form of provident
fund would be

a)Rs.48,456

b)Rs.48,540

c)Rs.44,856

d)Rs.45,480

Answer: a)

Explanation:
Annual provident fund savings =12%of(Rs.33650×12)
=Rs.12×33650×12/100 =Rs.48456

4).After provident fund deductions and payment
of house rent, the total monthly income of the family remains

a)Rs.23,545

b)Rs.24,435

c)Rs.23,555

d)Rs.25,355

Answer: c)

Explanation:
Remaining monthly income =[100-(12+18%] of Rs.33650
=Rs.70×33650/100 =Rs.23555

5).The total amount per month, the family spends
on food and entertainment combined together, is:

a)Rs.11,432

b)Rs.11,441

c)Rs.12,315

d)Rs.12,443

Answer: b)

Explanation:
Amount spent on food and entertainment together =34% of Rs.33650
=Rs.34×33650/100
=Rs.11441

6).The largest among the numbers (0.1)^{2},√0.0121,
0.12 and √0.0004 is

7).If 1!+2!+3!+4!+………+100! Is divided by 8, then
the remainder is

a)1

b)2

c)3

d)5

Answer: a)

Explanation:
.└2 is exactly divisible by 2.
└3 is exactly divisible by 3.
└4 is exactly divisible by 4.
Hence,└n is divisible by n.
(n!=1×2× 3 ×4 …..(n-1)× n)
∴ └8+└9+└10+……..└100
Is divisible by 8
Now, └1+└2+└3+……..+└7
=1+2+6+24+120+720+5040 =5193
∴Required remainder =Remainder obtained on dividing 5913 by 8 =1

8).The last digit of 3^{40} is

a)1

b)3

c)7

d)9

Answer: b)

Explanation:
31=3, 32=9, 33=27, 34=81, 35=343,……..
∴Required remainder on dividing 40 by 4 =0
∴Unit’s digit in 340=1

9).30 men can repair a road in 18 days. They
are joined by 6 more workers. Now the road can be repaired in

a)14 days

b)15 days

c)16 days

d)17 days

Answer: b)

Explanation:
M1D1 =M2D2
→30×18 =36× D2
→ D2=30×18/36 =15 days

10).A,B and C can complete a piece of work in
12, 24 and 36 days respectively. In how many days will they together complete
the same work?

a)5 6/11

b)4

c)6 6/11

d)6

Answer: c)

Explanation:
.(A+B+C)’s 1 day’s work
=1/12+1/24+1/36 =6+3+2/72 =11/2
∴(A+B+C) together will complete the work in 72/11 =6 6/11days.

Answers:

1).
d) 2). c) 3).
a) 4). c) 5).
b) 6). c) 7).
a) 8). a) 9).
b) 10). c)